What are the solutions to the equation (x+3)(2x-1)=0 ?

The solutions to the equation (x+3)(2x-1)=0 are x=-3,x= 1/2

Find the zeros of (x+3)(2x-1)=0

The zeros of (x+3)(2x-1)=0 are x=-3,x= 1/2

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(x + 3) (2 x - 1) = 0

x = - 3, x = \frac{1}{2}

Decimal Notation

x = - 3, x = 0.5

Solution steps

(x + 3) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or 2 x - 1 = 0

Solve

x + 3 = 0 : x = - 3

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = - 3, x = \frac{1}{2}

s^{2} + 3 s - 4 = 0

2 x^{2} + 8 x - 5

- x^{2} + 3 x - 10 = 0

x, ln (y) = x^{2} y

- a^{2} + 9 a - 18 = 0

What are the solutions to the equation (x+3)(2x-1)=0 ?
The solutions to the equation (x+3)(2x-1)=0 are x=-3,x= 1/2
Find the zeros of (x+3)(2x-1)=0
The zeros of (x+3)(2x-1)=0 are x=-3,x= 1/2