What are the solutions to the equation 3x^2+7x+20=0 ?

The solutions to the equation 3x^2+7x+20=0 are x=-7/6+i(sqrt(191))/6 ,x=-7/6-i(sqrt(191))/6

Find the zeros of 3x^2+7x+20=0

The zeros of 3x^2+7x+20=0 are x=-7/6+i(sqrt(191))/6 ,x=-7/6-i(sqrt(191))/6

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3 x^{2} + 7 x + 20 = 0

x = - \frac{7}{6} + i \frac{191}{6}, x = - \frac{7}{6} - i \frac{191}{6}

Solution steps

3 x^{2} + 7 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 \cdot 20}{2 \cdot 3}

Simplify

7^{2} - 4 \cdot 3 \cdot 20 : 191 i

x_{1, 2} = \frac{- 7 \pm 191 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 191 i}{2 \cdot 3}, x_{2} = \frac{- 7 - 191 i}{2 \cdot 3}

x = \frac{- 7 + 191 i}{2 \cdot 3} : - \frac{7}{6} + i \frac{191}{6}

x = \frac{- 7 - 191 i}{2 \cdot 3} : - \frac{7}{6} - i \frac{191}{6}

The solutions to the quadratic equation are:

x = - \frac{7}{6} + i \frac{191}{6}, x = - \frac{7}{6} - i \frac{191}{6}

2 (x + 1)^{2} = (2 x + 2)^{2}

x^{2} - 4 + 5 = 0

1 + 2 (x + 3)^{2} = 17

x^{2} = - 5 x + 6

26 = 6 + 37 t - 16 t^{2}

What are the solutions to the equation 3x^2+7x+20=0 ?
The solutions to the equation 3x^2+7x+20=0 are x=-7/6+i(sqrt(191))/6 ,x=-7/6-i(sqrt(191))/6
Find the zeros of 3x^2+7x+20=0
The zeros of 3x^2+7x+20=0 are x=-7/6+i(sqrt(191))/6 ,x=-7/6-i(sqrt(191))/6