What are the solutions to the equation 24+9x=10-4x(x+1) ?

The solutions to the equation 24+9x=10-4x(x+1) are x=-13/8-i(sqrt(55))/8 ,x=-13/8+i(sqrt(55))/8

Find the zeros of 24+9x=10-4x(x+1)

The zeros of 24+9x=10-4x(x+1) are x=-13/8-i(sqrt(55))/8 ,x=-13/8+i(sqrt(55))/8

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24 + 9 x = 10 - 4 x (x + 1)

x = - \frac{13}{8} - i \frac{55}{8}, x = - \frac{13}{8} + i \frac{55}{8}

Solution steps

24 + 9 x = 10 - 4 x (x + 1)

Expand

10 - 4 x (x + 1) : 10 - 4 x^{2} - 4 x

24 + 9 x = 10 - 4 x^{2} - 4 x

Switch sides

10 - 4 x^{2} - 4 x = 24 + 9 x

Move

9 x

to the left side

10 - 4 x^{2} - 13 x = 24

Move

24

to the left side

- 4 x^{2} - 13 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 ( - 4 ) ( - 14 )}{2 ( - 4 )}

Simplify

(- 13)^{2} - 4 (- 4) (- 14) : 55 i

x_{1, 2} = \frac{- ( - 13 ) \pm 55 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 55 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 13 ) - 55 i}{2 ( - 4 )}

x = \frac{- ( - 13 ) + 55 i}{2 ( - 4 )} : - \frac{13}{8} - i \frac{55}{8}

x = \frac{- ( - 13 ) - 55 i}{2 ( - 4 )} : - \frac{13}{8} + i \frac{55}{8}

The solutions to the quadratic equation are:

x = - \frac{13}{8} - i \frac{55}{8}, x = - \frac{13}{8} + i \frac{55}{8}

d = \frac{a t ^{2}}{2}

- x^{2} + 5 x + 14 = 0

- 3 x^{2} - 36 x - 100

6 y + 10 = y^{2} + 3 y

16 y^{2} - 25 = 0

What are the solutions to the equation 24+9x=10-4x(x+1) ?
The solutions to the equation 24+9x=10-4x(x+1) are x=-13/8-i(sqrt(55))/8 ,x=-13/8+i(sqrt(55))/8
Find the zeros of 24+9x=10-4x(x+1)
The zeros of 24+9x=10-4x(x+1) are x=-13/8-i(sqrt(55))/8 ,x=-13/8+i(sqrt(55))/8