What are the solutions to the equation -x^2+5x+14=0 ?

The solutions to the equation -x^2+5x+14=0 are x=-2,x=7

Find the zeros of -x^2+5x+14=0

The zeros of -x^2+5x+14=0 are x=-2,x=7

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- x^{2} + 5 x + 14 = 0

x = - 2, x = 7

Solution steps

- x^{2} + 5 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 14}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 14 = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 9}{2 ( - 1 )}, x_{2} = \frac{- 5 - 9}{2 ( - 1 )}

x = \frac{- 5 + 9}{2 ( - 1 )} : - 2

x = \frac{- 5 - 9}{2 ( - 1 )} : 7

The solutions to the quadratic equation are:

x = - 2, x = 7

- 3 x^{2} - 36 x - 100

6 y + 10 = y^{2} + 3 y

16 y^{2} - 25 = 0

(4 x + 9)^{2} = 25

(x + 10) (x - 5) = 0

What are the solutions to the equation -x^2+5x+14=0 ?
The solutions to the equation -x^2+5x+14=0 are x=-2,x=7
Find the zeros of -x^2+5x+14=0
The zeros of -x^2+5x+14=0 are x=-2,x=7