What are the solutions to the equation 3x^2+2x=-9 ?

The solutions to the equation 3x^2+2x=-9 are x=-1/3+i(sqrt(26))/3 ,x=-1/3-i(sqrt(26))/3

Find the zeros of 3x^2+2x=-9

The zeros of 3x^2+2x=-9 are x=-1/3+i(sqrt(26))/3 ,x=-1/3-i(sqrt(26))/3

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3 x^{2} + 2 x = - 9

x = - \frac{1}{3} + i \frac{26}{3}, x = - \frac{1}{3} - i \frac{26}{3}

Solution steps

3 x^{2} + 2 x = - 9

Move

9

to the left side

3 x^{2} + 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

2^{2} - 4 \cdot 3 \cdot 9 : 226 i

x_{1, 2} = \frac{- 2 \pm 2 26 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 26 i}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 26 i}{2 \cdot 3}

x = \frac{- 2 + 2 26 i}{2 \cdot 3} : - \frac{1}{3} + i \frac{26}{3}

x = \frac{- 2 - 2 26 i}{2 \cdot 3} : - \frac{1}{3} - i \frac{26}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{26}{3}, x = - \frac{1}{3} - i \frac{26}{3}

x (13 + x) + 6 = 42

x^{2} + 4 x + 1 = 0

6 x = x^{2} - 27

3 x^{2} - 12 x + 27 = 0

a^{2} - 7 a

What are the solutions to the equation 3x^2+2x=-9 ?
The solutions to the equation 3x^2+2x=-9 are x=-1/3+i(sqrt(26))/3 ,x=-1/3-i(sqrt(26))/3
Find the zeros of 3x^2+2x=-9
The zeros of 3x^2+2x=-9 are x=-1/3+i(sqrt(26))/3 ,x=-1/3-i(sqrt(26))/3