What are the solutions to the equation 3x^2-12x+27=0 ?

The solutions to the equation 3x^2-12x+27=0 are x=2+sqrt(5)i,x=2-sqrt(5)i

Find the zeros of 3x^2-12x+27=0

The zeros of 3x^2-12x+27=0 are x=2+sqrt(5)i,x=2-sqrt(5)i

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3 x^{2} - 12 x + 27 = 0

x = 2 + 5 i, x = 2 - 5 i

Solution steps

3 x^{2} - 12 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 27}{2 \cdot 3}

Simplify

(- 12)^{2} - 4 \cdot 3 \cdot 27 : 65 i

x_{1, 2} = \frac{- ( - 12 ) \pm 6 5 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 5 i}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 6 5 i}{2 \cdot 3}

x = \frac{- ( - 12 ) + 6 5 i}{2 \cdot 3} : 2 + 5 i

x = \frac{- ( - 12 ) - 6 5 i}{2 \cdot 3} : 2 - 5 i

The solutions to the quadratic equation are:

x = 2 + 5 i, x = 2 - 5 i

a^{2} - 7 a

4 x^{2} - 8 x = 52

9 x^{2} + 8 x - 5 = 3 x^{2}

y, x^{3} y^{2} - 6 x^{2} = 3 y^{2} - 9 x

1 0^{2} = x^{2} + (x + 2)^{2}

What are the solutions to the equation 3x^2-12x+27=0 ?
The solutions to the equation 3x^2-12x+27=0 are x=2+sqrt(5)i,x=2-sqrt(5)i
Find the zeros of 3x^2-12x+27=0
The zeros of 3x^2-12x+27=0 are x=2+sqrt(5)i,x=2-sqrt(5)i