What are the solutions to the equation -6x=x^2+9 ?

The solutions to the equation -6x=x^2+9 are x=-3

Find the zeros of -6x=x^2+9

The zeros of -6x=x^2+9 are x=-3

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- 6 x = x^{2} + 9

x = - 3

Solution steps

- 6 x = x^{2} + 9

Switch sides

x^{2} + 9 = - 6 x

Move

6 x

to the left side

x^{2} + 9 + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

x = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

x, f = I n (3 x^{2} - 5 x + 2)

x^{2} + 2 x = - 15

x^{2} - 1 = 0

a^{2} = 2 a + 3

x^{2} - 9 x + 14 = 0

What are the solutions to the equation -6x=x^2+9 ?
The solutions to the equation -6x=x^2+9 are x=-3
Find the zeros of -6x=x^2+9
The zeros of -6x=x^2+9 are x=-3