What are the solutions to the equation x^2+2x+1=64 ?

The solutions to the equation x^2+2x+1=64 are x=7,x=-9

Find the zeros of x^2+2x+1=64

The zeros of x^2+2x+1=64 are x=7,x=-9

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x^{2} + 2 x + 1 = 64

x = 7, x = - 9

Solution steps

x^{2} + 2 x + 1 = 64

Move

64

to the left side

x^{2} + 2 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 63 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 63) = 16

x_{1, 2} = \frac{- 2 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 16}{2 \cdot 1}, x_{2} = \frac{- 2 - 16}{2 \cdot 1}

x = \frac{- 2 + 16}{2 \cdot 1} : 7

x = \frac{- 2 - 16}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 7, x = - 9

- x^{2} + 2 x + 7 = 0

\frac{x ^{2}}{3} - \frac{x ( x - 1 )}{4} - 1 = (x^{2} - 1)

3 x^{2} - 1 = 4 λ x, - y = 2 λ x, x^{2} + y^{2} = 1

2 a x^{2} + (3 a - 1) x + a + b = 0

x^{2} + 2 x + 7 = x + 7

What are the solutions to the equation x^2+2x+1=64 ?
The solutions to the equation x^2+2x+1=64 are x=7,x=-9
Find the zeros of x^2+2x+1=64
The zeros of x^2+2x+1=64 are x=7,x=-9