What are the solutions to the equation 16x^2+10x-9=0 ?

The solutions to the equation 16x^2+10x-9=0 are x= 1/2 ,x=-9/8

Find the zeros of 16x^2+10x-9=0

The zeros of 16x^2+10x-9=0 are x= 1/2 ,x=-9/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 x^{2} + 10 x - 9 = 0

x = \frac{1}{2}, x = - \frac{9}{8}

Decimal Notation

x = 0.5, x = - 1.125

Solution steps

16 x^{2} + 10 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 16 ( - 9 )}{2 \cdot 16}

1 0^{2} - 4 \cdot 16 (- 9) = 26

x_{1, 2} = \frac{- 10 \pm 26}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 10 + 26}{2 \cdot 16}, x_{2} = \frac{- 10 - 26}{2 \cdot 16}

x = \frac{- 10 + 26}{2 \cdot 16} : \frac{1}{2}

x = \frac{- 10 - 26}{2 \cdot 16} : - \frac{9}{8}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{9}{8}

4 (x + 2)^{2} = 16

z^{2} - 100 = 0

9 x^{2} - 60 x + 75 = 0

x^{2} - 5 x - 9

x^{2} - 5 x + 4

What are the solutions to the equation 16x^2+10x-9=0 ?
The solutions to the equation 16x^2+10x-9=0 are x= 1/2 ,x=-9/8
Find the zeros of 16x^2+10x-9=0
The zeros of 16x^2+10x-9=0 are x= 1/2 ,x=-9/8