What are the solutions to the equation -3x^2+x+2=0 ?

The solutions to the equation -3x^2+x+2=0 are x=-2/3 ,x=1

Find the zeros of -3x^2+x+2=0

The zeros of -3x^2+x+2=0 are x=-2/3 ,x=1

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- 3 x^{2} + x + 2 = 0

x = - \frac{2}{3}, x = 1

Decimal

x = - 0.66666 \dots, x = 1

Solution steps

- 3 x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

1^{2} - 4 (- 3) \cdot 2 = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 ( - 3 )}, x_{2} = \frac{- 1 - 5}{2 ( - 3 )}

x = \frac{- 1 + 5}{2 ( - 3 )} : - \frac{2}{3}

x = \frac{- 1 - 5}{2 ( - 3 )} : 1

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = 1

r^{2} - 4 r + 1 = 0

t^{2} + 5 t - 14 = 0

0.000006 x^{2} - 0.02 x + 25 = 35

3 x^{2} = x^{2} + 50

120 - 104 x + 12 x^{2} = 0

What are the solutions to the equation -3x^2+x+2=0 ?
The solutions to the equation -3x^2+x+2=0 are x=-2/3 ,x=1
Find the zeros of -3x^2+x+2=0
The zeros of -3x^2+x+2=0 are x=-2/3 ,x=1