What are the solutions to the equation 120-104x+12x^2=0 ?

The solutions to the equation 120-104x+12x^2=0 are x=(13+sqrt(79))/3 ,x=(13-sqrt(79))/3

Find the zeros of 120-104x+12x^2=0

The zeros of 120-104x+12x^2=0 are x=(13+sqrt(79))/3 ,x=(13-sqrt(79))/3

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120 - 104 x + 12 x^{2} = 0

x = \frac{13 + 79}{3}, x = \frac{13 - 79}{3}

Decimal Notation

x = 7.29606 \dots, x = 1.37060 \dots

Solution steps

120 - 104 x + 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 104 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 104 ) \pm ( - 104 ) ^{2} - 4 \cdot 12 \cdot 120}{2 \cdot 12}

(- 104)^{2} - 4 \cdot 12 \cdot 120 = 879

x_{1, 2} = \frac{- ( - 104 ) \pm 8 79}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 104 ) + 8 79}{2 \cdot 12}, x_{2} = \frac{- ( - 104 ) - 8 79}{2 \cdot 12}

x = \frac{- ( - 104 ) + 8 79}{2 \cdot 12} : \frac{13 + 79}{3}

x = \frac{- ( - 104 ) - 8 79}{2 \cdot 12} : \frac{13 - 79}{3}

The solutions to the quadratic equation are:

x = \frac{13 + 79}{3}, x = \frac{13 - 79}{3}

x^{2} - 13 x = - 36

x^{2} - 13 x = - 30

0 = - 2 x^{2} + 4 x + 1

- 3 x^{2} + 16 x - 10 = 0

(x - \frac{3}{2})^{2} = \frac{25}{4}

What are the solutions to the equation 120-104x+12x^2=0 ?
The solutions to the equation 120-104x+12x^2=0 are x=(13+sqrt(79))/3 ,x=(13-sqrt(79))/3
Find the zeros of 120-104x+12x^2=0
The zeros of 120-104x+12x^2=0 are x=(13+sqrt(79))/3 ,x=(13-sqrt(79))/3