What are the solutions to the equation -4x^2+12x+9=0 ?

The solutions to the equation -4x^2+12x+9=0 are x=-(3(sqrt(2)-1))/2 ,x=(3(1+sqrt(2)))/2

Find the zeros of -4x^2+12x+9=0

The zeros of -4x^2+12x+9=0 are x=-(3(sqrt(2)-1))/2 ,x=(3(1+sqrt(2)))/2

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- 4 x^{2} + 12 x + 9 = 0

x = - \frac{3 ( 2 - 1 )}{2}, x = \frac{3 ( 1 + 2 )}{2}

Decimal Notation

x = - 0.62132 \dots, x = 3.62132 \dots

Solution steps

- 4 x^{2} + 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 4 ) \cdot 9}{2 ( - 4 )}

1 2^{2} - 4 (- 4) \cdot 9 = 122

x_{1, 2} = \frac{- 12 \pm 12 2}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 12 + 12 2}{2 ( - 4 )}, x_{2} = \frac{- 12 - 12 2}{2 ( - 4 )}

x = \frac{- 12 + 12 2}{2 ( - 4 )} : - \frac{3 ( 2 - 1 )}{2}

x = \frac{- 12 - 12 2}{2 ( - 4 )} : \frac{3 ( 1 + 2 )}{2}

The solutions to the quadratic equation are:

x = - \frac{3 ( 2 - 1 )}{2}, x = \frac{3 ( 1 + 2 )}{2}

- 2 x^{2} + 4 x + 30 = 0

x^{2} + 2 x^{2} - x - 2 = 0

2 x^{2} + 2 x - x - 1 = 0

\frac{n ( 3 n + 1 )}{2} = 200

36 x^{2} + 24 x + 4 = 0

What are the solutions to the equation -4x^2+12x+9=0 ?
The solutions to the equation -4x^2+12x+9=0 are x=-(3(sqrt(2)-1))/2 ,x=(3(1+sqrt(2)))/2
Find the zeros of -4x^2+12x+9=0
The zeros of -4x^2+12x+9=0 are x=-(3(sqrt(2)-1))/2 ,x=(3(1+sqrt(2)))/2