What are the solutions to the equation -2x^2+4x+30=0 ?

The solutions to the equation -2x^2+4x+30=0 are x=-3,x=5

Find the zeros of -2x^2+4x+30=0

The zeros of -2x^2+4x+30=0 are x=-3,x=5

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- 2 x^{2} + 4 x + 30 = 0

x = - 3, x = 5

Solution steps

- 2 x^{2} + 4 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) \cdot 30}{2 ( - 2 )}

4^{2} - 4 (- 2) \cdot 30 = 16

x_{1, 2} = \frac{- 4 \pm 16}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 16}{2 ( - 2 )}, x_{2} = \frac{- 4 - 16}{2 ( - 2 )}

x = \frac{- 4 + 16}{2 ( - 2 )} : - 3

x = \frac{- 4 - 16}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = - 3, x = 5

x^{2} + 2 x^{2} - x - 2 = 0

2 x^{2} + 2 x - x - 1 = 0

\frac{n ( 3 n + 1 )}{2} = 200

36 x^{2} + 24 x + 4 = 0

f^{2} + 6 f + 9 = 0

What are the solutions to the equation -2x^2+4x+30=0 ?
The solutions to the equation -2x^2+4x+30=0 are x=-3,x=5
Find the zeros of -2x^2+4x+30=0
The zeros of -2x^2+4x+30=0 are x=-3,x=5