What are the solutions to the equation solvefor x,12x^2-8xs+s^2=0 ?

The solutions to the equation solvefor x,12x^2-8xs+s^2=0 are x= s/2 ,x= s/6

Find the zeros of solvefor x,12x^2-8xs+s^2=0

The zeros of solvefor x,12x^2-8xs+s^2=0 are x= s/2 ,x= s/6

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solve for

x, 12 x^{2} - 8 x s + s^{2} = 0

x = \frac{s}{2}, x = \frac{s}{6}

Solution steps

12 x^{2} - 8 x s + s^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 8 s x + s^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 s ) \pm ( - 8 s ) ^{2} - 4 \cdot 12 s ^{2}}{2 \cdot 12}

Simplify

(- 8 s)^{2} - 4 \cdot 12 s^{2} : 4 s

x_{1, 2} = \frac{- ( - 8 s ) \pm 4 s}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 8 s ) + 4 s}{2 \cdot 12}, x_{2} = \frac{- ( - 8 s ) - 4 s}{2 \cdot 12}

x = \frac{- ( - 8 s ) + 4 s}{2 \cdot 12} : \frac{s}{2}

x = \frac{- ( - 8 s ) - 4 s}{2 \cdot 12} : \frac{s}{6}

The solutions to the quadratic equation are:

x = \frac{s}{2}, x = \frac{s}{6}

- 3 x^{2} - 27 = 0

b^{2} = 121

y, (3 x y - x^{2})^{2} = 2 y + x y

x^{2} + 4 x - 5 = 0

x (4 x - 5) = 12

What are the solutions to the equation solvefor x,12x^2-8xs+s^2=0 ?
The solutions to the equation solvefor x,12x^2-8xs+s^2=0 are x= s/2 ,x= s/6
Find the zeros of solvefor x,12x^2-8xs+s^2=0
The zeros of solvefor x,12x^2-8xs+s^2=0 are x= s/2 ,x= s/6