What are the solutions to the equation x(4x-5)=12 ?

The solutions to the equation x(4x-5)=12 are x=(5+sqrt(217))/8 ,x=(5-sqrt(217))/8

Find the zeros of x(4x-5)=12

The zeros of x(4x-5)=12 are x=(5+sqrt(217))/8 ,x=(5-sqrt(217))/8

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x (4 x - 5) = 12

x = \frac{5 + 217}{8}, x = \frac{5 - 217}{8}

Decimal Notation

x = 2.46636 \dots, x = - 1.21636 \dots

Solution steps

x (4 x - 5) = 12

Expand

x (4 x - 5) : 4 x^{2} - 5 x

4 x^{2} - 5 x = 12

Move

12

to the left side

4 x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 12 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 12) = 217

x_{1, 2} = \frac{- ( - 5 ) \pm 217}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 217}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 217}{2 \cdot 4}

x = \frac{- ( - 5 ) + 217}{2 \cdot 4} : \frac{5 + 217}{8}

x = \frac{- ( - 5 ) - 217}{2 \cdot 4} : \frac{5 - 217}{8}

The solutions to the quadratic equation are:

x = \frac{5 + 217}{8}, x = \frac{5 - 217}{8}

3 a^{2} + 6 a - 45 = 0

12 x^{2} + 24 x - 36 = 0

g (n) = n^{2} - 4, g (- 5)

4 y^{2} - 12 y + 9 = 0

x, x^{2} - x - 6 = 0

What are the solutions to the equation x(4x-5)=12 ?
The solutions to the equation x(4x-5)=12 are x=(5+sqrt(217))/8 ,x=(5-sqrt(217))/8
Find the zeros of x(4x-5)=12
The zeros of x(4x-5)=12 are x=(5+sqrt(217))/8 ,x=(5-sqrt(217))/8