What are the solutions to the equation 3a^2+6a-45=0 ?

The solutions to the equation 3a^2+6a-45=0 are a=3,a=-5

Find the zeros of 3a^2+6a-45=0

The zeros of 3a^2+6a-45=0 are a=3,a=-5

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3 a^{2} + 6 a - 45 = 0

a = 3, a = - 5

Solution steps

3 a^{2} + 6 a - 45 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 45 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 45) = 24

a_{1, 2} = \frac{- 6 \pm 24}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- 6 + 24}{2 \cdot 3}, a_{2} = \frac{- 6 - 24}{2 \cdot 3}

a = \frac{- 6 + 24}{2 \cdot 3} : 3

a = \frac{- 6 - 24}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

a = 3, a = - 5

12 x^{2} + 24 x - 36 = 0

g (n) = n^{2} - 4, g (- 5)

4 y^{2} - 12 y + 9 = 0

x, x^{2} - x - 6 = 0

6 x^{2} + 3 x - 2 = 0

What are the solutions to the equation 3a^2+6a-45=0 ?
The solutions to the equation 3a^2+6a-45=0 are a=3,a=-5
Find the zeros of 3a^2+6a-45=0
The zeros of 3a^2+6a-45=0 are a=3,a=-5