What are the solutions to the equation 12x^2+24x-36=0 ?

The solutions to the equation 12x^2+24x-36=0 are x=1,x=-3

Find the zeros of 12x^2+24x-36=0

The zeros of 12x^2+24x-36=0 are x=1,x=-3

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12 x^{2} + 24 x - 36 = 0

x = 1, x = - 3

Solution steps

12 x^{2} + 24 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 12 ( - 36 )}{2 \cdot 12}

2 4^{2} - 4 \cdot 12 (- 36) = 48

x_{1, 2} = \frac{- 24 \pm 48}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 24 + 48}{2 \cdot 12}, x_{2} = \frac{- 24 - 48}{2 \cdot 12}

x = \frac{- 24 + 48}{2 \cdot 12} : 1

x = \frac{- 24 - 48}{2 \cdot 12} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

g (n) = n^{2} - 4, g (- 5)

4 y^{2} - 12 y + 9 = 0

x, x^{2} - x - 6 = 0

6 x^{2} + 3 x - 2 = 0

2 k^{2} + 5 k + 1 = 0

What are the solutions to the equation 12x^2+24x-36=0 ?
The solutions to the equation 12x^2+24x-36=0 are x=1,x=-3
Find the zeros of 12x^2+24x-36=0
The zeros of 12x^2+24x-36=0 are x=1,x=-3