What are the solutions to the equation 2k^2+5k+1=0 ?

The solutions to the equation 2k^2+5k+1=0 are k=(-5+sqrt(17))/4 ,k=(-5-sqrt(17))/4

Find the zeros of 2k^2+5k+1=0

The zeros of 2k^2+5k+1=0 are k=(-5+sqrt(17))/4 ,k=(-5-sqrt(17))/4

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2 k^{2} + 5 k + 1 = 0

k = \frac{- 5 + 17}{4}, k = \frac{- 5 - 17}{4}

Decimal Notation

k = - 0.21922 \dots, k = - 2.28077 \dots

Solution steps

2 k^{2} + 5 k + 1 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 1 = 17

k_{1, 2} = \frac{- 5 \pm 17}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 5 + 17}{2 \cdot 2}, k_{2} = \frac{- 5 - 17}{2 \cdot 2}

k = \frac{- 5 + 17}{2 \cdot 2} : \frac{- 5 + 17}{4}

k = \frac{- 5 - 17}{2 \cdot 2} : \frac{- 5 - 17}{4}

The solutions to the quadratic equation are:

k = \frac{- 5 + 17}{4}, k = \frac{- 5 - 17}{4}

s^{2} - 8 s + 15 = 0

x^{2} - 20 x + 87 = 0

m^{2} - 15 m + 56 = 0

x = 0.5714 - 2000 (0.00249 (1 - \frac{x}{- 2})^{2})

(6 + x) (4 + x) = 2 (24)

What are the solutions to the equation 2k^2+5k+1=0 ?
The solutions to the equation 2k^2+5k+1=0 are k=(-5+sqrt(17))/4 ,k=(-5-sqrt(17))/4
Find the zeros of 2k^2+5k+1=0
The zeros of 2k^2+5k+1=0 are k=(-5+sqrt(17))/4 ,k=(-5-sqrt(17))/4