What are the solutions to the equation m^2-15m+56=0 ?

The solutions to the equation m^2-15m+56=0 are m=8,m=7

Find the zeros of m^2-15m+56=0

The zeros of m^2-15m+56=0 are m=8,m=7

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m^{2} - 15 m + 56 = 0

m = 8, m = 7

Solution steps

m^{2} - 15 m + 56 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 56 = 1

m_{1, 2} = \frac{- ( - 15 ) \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 15 ) + 1}{2 \cdot 1}, m_{2} = \frac{- ( - 15 ) - 1}{2 \cdot 1}

m = \frac{- ( - 15 ) + 1}{2 \cdot 1} : 8

m = \frac{- ( - 15 ) - 1}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

m = 8, m = 7

x = 0.5714 - 2000 (0.00249 (1 - \frac{x}{- 2})^{2})

(6 + x) (4 + x) = 2 (24)

0 = x^{2} - 15 x + 54

5 x^{2} - 35 + 60 = 0

4 k (k + 14) = 14

What are the solutions to the equation m^2-15m+56=0 ?
The solutions to the equation m^2-15m+56=0 are m=8,m=7
Find the zeros of m^2-15m+56=0
The zeros of m^2-15m+56=0 are m=8,m=7