What are the solutions to the equation x(x+4)=-3 ?

The solutions to the equation x(x+4)=-3 are x=-1,x=-3

Find the zeros of x(x+4)=-3

The zeros of x(x+4)=-3 are x=-1,x=-3

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x (x + 4) = - 3

x = - 1, x = - 3

Solution steps

x (x + 4) = - 3

Expand

x (x + 4) : x^{2} + 4 x

x^{2} + 4 x = - 3

Move

3

to the left side

x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2}{2 \cdot 1}

x = \frac{- 4 + 2}{2 \cdot 1} : - 1

x = \frac{- 4 - 2}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

(3 k + 2)^{2} = 49

x, 615 + x^{2} = 2^{y}

2 x^{2} + 11 x - 15 = 0

3 y^{2} = - 4 y + 16

(x - 8)^{2} = 44

What are the solutions to the equation x(x+4)=-3 ?
The solutions to the equation x(x+4)=-3 are x=-1,x=-3
Find the zeros of x(x+4)=-3
The zeros of x(x+4)=-3 are x=-1,x=-3