What are the solutions to the equation -x^2-6x-4=0 ?

The solutions to the equation -x^2-6x-4=0 are x=-3-sqrt(5),x=-3+sqrt(5)

Find the zeros of -x^2-6x-4=0

The zeros of -x^2-6x-4=0 are x=-3-sqrt(5),x=-3+sqrt(5)

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- x^{2} - 6 x - 4 = 0

x = - 3 - 5, x = - 3 + 5

Decimal Notation

x = - 5.23606 \dots, x = - 0.76393 \dots

Solution steps

- x^{2} - 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) (- 4) = 25

x_{1, 2} = \frac{- ( - 6 ) \pm 2 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 2 5}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 2 5}{2 ( - 1 )} : - 3 - 5

x = \frac{- ( - 6 ) - 2 5}{2 ( - 1 )} : - 3 + 5

The solutions to the quadratic equation are:

x = - 3 - 5, x = - 3 + 5

4 x^{2} = 6 x + 28

X^{2} = 64

3.5 y^{2} - 0.1 y - 0.6 = 0

3 x^{2} - x + 5 = 7

3 x^{2} + 108 = 0

What are the solutions to the equation -x^2-6x-4=0 ?
The solutions to the equation -x^2-6x-4=0 are x=-3-sqrt(5),x=-3+sqrt(5)
Find the zeros of -x^2-6x-4=0
The zeros of -x^2-6x-4=0 are x=-3-sqrt(5),x=-3+sqrt(5)