What are the solutions to the equation 3x^2-x+5=7 ?

The solutions to the equation 3x^2-x+5=7 are x=1,x=-2/3

Find the zeros of 3x^2-x+5=7

The zeros of 3x^2-x+5=7 are x=1,x=-2/3

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3 x^{2} - x + 5 = 7

x = 1, x = - \frac{2}{3}

Decimal Notation

x = 1, x = - 0.66666 \dots

Solution steps

3 x^{2} - x + 5 = 7

Move

7

to the left side

3 x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 2) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 3}

x = \frac{- ( - 1 ) + 5}{2 \cdot 3} : 1

x = \frac{- ( - 1 ) - 5}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{2}{3}

3 x^{2} + 108 = 0

(x) = x^{2} + 4 x + 5

(2 x + a)^{2} = b

x^{2} + 8 x = 14

29 - 5 x = x^{2} - 2 x + 1

What are the solutions to the equation 3x^2-x+5=7 ?
The solutions to the equation 3x^2-x+5=7 are x=1,x=-2/3
Find the zeros of 3x^2-x+5=7
The zeros of 3x^2-x+5=7 are x=1,x=-2/3