What are the solutions to the equation (2x+a)^2=b ?

The solutions to the equation (2x+a)^2=b are x=(sqrt(b)-a)/2 ,x=(-sqrt(b)-a)/2

Find the zeros of (2x+a)^2=b

The zeros of (2x+a)^2=b are x=(sqrt(b)-a)/2 ,x=(-sqrt(b)-a)/2

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(2 x + a)^{2} = b

x = \frac{b - a}{2}, x = \frac{- b - a}{2}

Solution steps

(2 x + a)^{2} = b

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + a = b : x = \frac{b - a}{2}

Solve

2 x + a = - b : x = \frac{- b - a}{2}

The solutions to the quadratic equation are:

x = \frac{b - a}{2}, x = \frac{- b - a}{2}

x^{2} + 8 x = 14

29 - 5 x = x^{2} - 2 x + 1

x^{2} + 8 x = 38

x, 2 x^{2} + 4 x - 7 = 0

x^{2} + 8 x = - 8

What are the solutions to the equation (2x+a)^2=b ?
The solutions to the equation (2x+a)^2=b are x=(sqrt(b)-a)/2 ,x=(-sqrt(b)-a)/2
Find the zeros of (2x+a)^2=b
The zeros of (2x+a)^2=b are x=(sqrt(b)-a)/2 ,x=(-sqrt(b)-a)/2