What are the solutions to the equation X^2+2X+2=0 ?

The solutions to the equation X^2+2X+2=0 are X=-1+i,X=-1-i

Find the zeros of X^2+2X+2=0

The zeros of X^2+2X+2=0 are X=-1+i,X=-1-i

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X^{2} + 2 X + 2 = 0

X = - 1 + i, X = - 1 - i

Solution steps

X^{2} + 2 X + 2 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

X_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, X_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

X = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

X = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

X = - 1 + i, X = - 1 - i

x^{2} + 7 x + 10 = 0

x, \frac{( x ^{2} + y ^{3} )}{y} - 4 x^{2} y = 4

- 7 x + 6 = - 4 x^{2}

- 5 - 7 + 1 x - 3 - 1 x^{2} + 6 x^{2} = - 5 x + 4 x + 4 x^{2}

k^{2} + 4 = 0

What are the solutions to the equation X^2+2X+2=0 ?
The solutions to the equation X^2+2X+2=0 are X=-1+i,X=-1-i
Find the zeros of X^2+2X+2=0
The zeros of X^2+2X+2=0 are X=-1+i,X=-1-i