What are the solutions to the equation -5-7+1x-3-1x^2+6x^2=-5x+4x+4x^2 ?

The solutions to the equation -5-7+1x-3-1x^2+6x^2=-5x+4x+4x^2 are x=3,x=-5

Find the zeros of -5-7+1x-3-1x^2+6x^2=-5x+4x+4x^2

The zeros of -5-7+1x-3-1x^2+6x^2=-5x+4x+4x^2 are x=3,x=-5

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- 5 - 7 + 1 x - 3 - 1 x^{2} + 6 x^{2} = - 5 x + 4 x + 4 x^{2}

x = 3, x = - 5

Solution steps

- 5 - 7 + 1 \cdot x - 3 - 1 \cdot x^{2} + 6 x^{2} = - 5 x + 4 x + 4 x^{2}

Refine

5 x^{2} + x - 15 = - x + 4 x^{2}

Move

4 x^{2}

to the left side

x^{2} + x - 15 = - x

Move

x

to the left side

x^{2} + 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

x_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 8}{2 \cdot 1}, x_{2} = \frac{- 2 - 8}{2 \cdot 1}

x = \frac{- 2 + 8}{2 \cdot 1} : 3

x = \frac{- 2 - 8}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 3, x = - 5

k^{2} + 4 = 0

x^{2} + \frac{2 x}{3} - \frac{1}{3}

2 - 2 y^{2} = 2 y^{2} - 2

x^{2} - 16 x - 80 = 0

6 z^{2} + 13 z + 6 = 0

What are the solutions to the equation -5-7+1x-3-1x^2+6x^2=-5x+4x+4x^2 ?
The solutions to the equation -5-7+1x-3-1x^2+6x^2=-5x+4x+4x^2 are x=3,x=-5
Find the zeros of -5-7+1x-3-1x^2+6x^2=-5x+4x+4x^2
The zeros of -5-7+1x-3-1x^2+6x^2=-5x+4x+4x^2 are x=3,x=-5