What are the solutions to the equation 0=-x^2-2x-1 ?

The solutions to the equation 0=-x^2-2x-1 are x=-1

Find the zeros of 0=-x^2-2x-1

The zeros of 0=-x^2-2x-1 are x=-1

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0 = - x^{2} - 2 x - 1

x = - 1

Solution steps

0 = - x^{2} - 2 x - 1

Switch sides

- x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) ( - 1 )}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) (- 1) = 0

x_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 2 )}{2 ( - 1 )}

\frac{- ( - 2 )}{2 ( - 1 )} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

x^{2} + 12 x + 38 = 0

- 4 x^{2} = - 36

4 x^{2} - 211 = - 15

x, 4 x^{2} + k x + 1 = 0

2 n^{2} - 9 = 119

What are the solutions to the equation 0=-x^2-2x-1 ?
The solutions to the equation 0=-x^2-2x-1 are x=-1
Find the zeros of 0=-x^2-2x-1
The zeros of 0=-x^2-2x-1 are x=-1