What are the solutions to the equation -4x^2+24x-41=0 ?

The solutions to the equation -4x^2+24x-41=0 are x=3-i(sqrt(5))/2 ,x=3+i(sqrt(5))/2

Find the zeros of -4x^2+24x-41=0

The zeros of -4x^2+24x-41=0 are x=3-i(sqrt(5))/2 ,x=3+i(sqrt(5))/2

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- 4 x^{2} + 24 x - 41 = 0

x = 3 - i \frac{5}{2}, x = 3 + i \frac{5}{2}

Solution steps

- 4 x^{2} + 24 x - 41 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 4 ) ( - 41 )}{2 ( - 4 )}

Simplify

2 4^{2} - 4 (- 4) (- 41) : 45 i

x_{1, 2} = \frac{- 24 \pm 4 5 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 24 + 4 5 i}{2 ( - 4 )}, x_{2} = \frac{- 24 - 4 5 i}{2 ( - 4 )}

x = \frac{- 24 + 4 5 i}{2 ( - 4 )} : 3 - i \frac{5}{2}

x = \frac{- 24 - 4 5 i}{2 ( - 4 )} : 3 + i \frac{5}{2}

The solutions to the quadratic equation are:

x = 3 - i \frac{5}{2}, x = 3 + i \frac{5}{2}

36 a^{2} - 6 = - 5

s^{2} - 4 s - 5 = 0

x^{2} - 12 x + 37

0 = 2 x^{2} + x - 1

8 x^{2} = 3 x + 6

What are the solutions to the equation -4x^2+24x-41=0 ?
The solutions to the equation -4x^2+24x-41=0 are x=3-i(sqrt(5))/2 ,x=3+i(sqrt(5))/2
Find the zeros of -4x^2+24x-41=0
The zeros of -4x^2+24x-41=0 are x=3-i(sqrt(5))/2 ,x=3+i(sqrt(5))/2