What are the solutions to the equation s^2-4s-4=0 ?

The solutions to the equation s^2-4s-4=0 are s=2(1+sqrt(2)),s=2(1-sqrt(2))

Find the zeros of s^2-4s-4=0

The zeros of s^2-4s-4=0 are s=2(1+sqrt(2)),s=2(1-sqrt(2))

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s^{2} - 4 s - 4 = 0

s = 2 (1 + 2), s = 2 (1 - 2)

Decimal Notation

s = 4.82842 \dots, s = - 0.82842 \dots

Solution steps

s^{2} - 4 s - 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 4) = 42

s_{1, 2} = \frac{- ( - 4 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 4 ) + 4 2}{2 \cdot 1}, s_{2} = \frac{- ( - 4 ) - 4 2}{2 \cdot 1}

s = \frac{- ( - 4 ) + 4 2}{2 \cdot 1} : 2 (1 + 2)

s = \frac{- ( - 4 ) - 4 2}{2 \cdot 1} : 2 (1 - 2)

The solutions to the quadratic equation are:

s = 2 (1 + 2), s = 2 (1 - 2)

x^{2} + 192 = 0

y, y^{2} + z^{2} = 0

(s - 1)^{2} = 0

224 - 24 q + 1.5 q^{2} = 0

4 + 20 x^{2} + 8 x = 0

What are the solutions to the equation s^2-4s-4=0 ?
The solutions to the equation s^2-4s-4=0 are s=2(1+sqrt(2)),s=2(1-sqrt(2))
Find the zeros of s^2-4s-4=0
The zeros of s^2-4s-4=0 are s=2(1+sqrt(2)),s=2(1-sqrt(2))