What are the solutions to the equation 9-4x^2=0 ?

The solutions to the equation 9-4x^2=0 are x= 3/2 ,x=-3/2

Find the zeros of 9-4x^2=0

The zeros of 9-4x^2=0 are x= 3/2 ,x=-3/2

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9 - 4 x^{2} = 0

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 1.5, x = - 1.5

Solution steps

9 - 4 x^{2} = 0

Move

9

to the right side

- 4 x^{2} = - 9

Divide both sides by

- 4

x^{2} = \frac{9}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{4}, x = - \frac{9}{4}

\frac{9}{4} = \frac{3}{2}

- \frac{9}{4} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

m^{2} - 4 m - 4 = 0

3 p^{2} + 1 = - 43

2 x^{2} - x

\frac{263}{160} \frac{A ^{2}}{2} \cdot 4 \cdot 1 0^{- 7} = 5 \cdot 1 0^{- 6}

6 x^{2} - 10 x + 1 = 0

What are the solutions to the equation 9-4x^2=0 ?
The solutions to the equation 9-4x^2=0 are x= 3/2 ,x=-3/2
Find the zeros of 9-4x^2=0
The zeros of 9-4x^2=0 are x= 3/2 ,x=-3/2