What are the solutions to the equation x^2+8x-6=-30 ?

The solutions to the equation x^2+8x-6=-30 are x=-4+2sqrt(2)i,x=-4-2sqrt(2)i

Find the zeros of x^2+8x-6=-30

The zeros of x^2+8x-6=-30 are x=-4+2sqrt(2)i,x=-4-2sqrt(2)i

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x^{2} + 8 x - 6 = - 30

x = - 4 + 22 i, x = - 4 - 22 i

Solution steps

x^{2} + 8 x - 6 = - 30

Move

30

to the left side

x^{2} + 8 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 24 : 42 i

x_{1, 2} = \frac{- 8 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 4 2 i}{2 \cdot 1}

x = \frac{- 8 + 4 2 i}{2 \cdot 1} : - 4 + 22 i

x = \frac{- 8 - 4 2 i}{2 \cdot 1} : - 4 - 22 i

The solutions to the quadratic equation are:

x = - 4 + 22 i, x = - 4 - 22 i

5 x^{2} - 3 x = - 10

3 x^{2} + 5 x + 11 = 0

\frac{1}{8} x^{2} + x + 2 = 0

\frac{x ^{2}}{2} = \frac{1}{6} + \frac{x}{12}

x^{2} - 2 x + \frac{1}{2} = 0

What are the solutions to the equation x^2+8x-6=-30 ?
The solutions to the equation x^2+8x-6=-30 are x=-4+2sqrt(2)i,x=-4-2sqrt(2)i
Find the zeros of x^2+8x-6=-30
The zeros of x^2+8x-6=-30 are x=-4+2sqrt(2)i,x=-4-2sqrt(2)i