What are the solutions to the equation 15x^2-3x=0 ?

The solutions to the equation 15x^2-3x=0 are x= 1/5 ,x=0

Find the zeros of 15x^2-3x=0

The zeros of 15x^2-3x=0 are x= 1/5 ,x=0

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15 x^{2} - 3 x = 0

x = \frac{1}{5}, x = 0

Decimal Notation

x = 0.2, x = 0

Solution steps

15 x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 15 \cdot 0}{2 \cdot 15}

(- 3)^{2} - 4 \cdot 15 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 15}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 15}

x = \frac{- ( - 3 ) + 3}{2 \cdot 15} : \frac{1}{5}

x = \frac{- ( - 3 ) - 3}{2 \cdot 15} : 0

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = 0

25 p^{2} + 70 p + 49 = 0

- 0.2 x^{2} + 1.6 x

m^{2} = 4 m - 3

x^{2} + 2 x + c

(x - 1)^{2} = 18

What are the solutions to the equation 15x^2-3x=0 ?
The solutions to the equation 15x^2-3x=0 are x= 1/5 ,x=0
Find the zeros of 15x^2-3x=0
The zeros of 15x^2-3x=0 are x= 1/5 ,x=0