What are the solutions to the equation 3p^2-2p-5=0 ?

The solutions to the equation 3p^2-2p-5=0 are p= 5/3 ,p=-1

Find the zeros of 3p^2-2p-5=0

The zeros of 3p^2-2p-5=0 are p= 5/3 ,p=-1

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3 p^{2} - 2 p - 5 = 0

p = \frac{5}{3}, p = - 1

Decimal Notation

p = 1.66666 \dots, p = - 1

Solution steps

3 p^{2} - 2 p - 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 5) = 8

p_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 3}, p_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 3}

p = \frac{- ( - 2 ) + 8}{2 \cdot 3} : \frac{5}{3}

p = \frac{- ( - 2 ) - 8}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

p = \frac{5}{3}, p = - 1

x^{2} + 9 x = 0

(x + 1)^{3} - (x - 1)^{3} = 7

4 x^{2} + 16 x = 65

3 y^{2} - 144 = 0

3 x^{2} - 6 x + 1 = 3

What are the solutions to the equation 3p^2-2p-5=0 ?
The solutions to the equation 3p^2-2p-5=0 are p= 5/3 ,p=-1
Find the zeros of 3p^2-2p-5=0
The zeros of 3p^2-2p-5=0 are p= 5/3 ,p=-1