What are the solutions to the equation (x+1)^3-(x-1)^3=7 ?

The solutions to the equation (x+1)^3-(x-1)^3=7 are x=sqrt(5/6),x=-sqrt(5/6)

Find the zeros of (x+1)^3-(x-1)^3=7

The zeros of (x+1)^3-(x-1)^3=7 are x=sqrt(5/6),x=-sqrt(5/6)

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(x + 1)^{3} - (x - 1)^{3} = 7

x = \frac{5}{6}, x = - \frac{5}{6}

Decimal Notation

x = 0.91287 \dots, x = - 0.91287 \dots

Solution steps

(x + 1)^{3} - (x - 1)^{3} = 7

Expand

(x + 1)^{3} - (x - 1)^{3} : 6 x^{2} + 2

6 x^{2} + 2 = 7

Move

7

to the left side

6 x^{2} - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

0^{2} - 4 \cdot 6 (- 5) = 230

x_{1, 2} = \frac{- 0 \pm 2 30}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 0 + 2 30}{2 \cdot 6}, x_{2} = \frac{- 0 - 2 30}{2 \cdot 6}

x = \frac{- 0 + 2 30}{2 \cdot 6} : \frac{5}{6}

x = \frac{- 0 - 2 30}{2 \cdot 6} : - \frac{5}{6}

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = - \frac{5}{6}

4 x^{2} + 16 x = 65

3 y^{2} - 144 = 0

3 x^{2} - 6 x + 1 = 3

λ^{2} + 3 λ + 2 = 0

145 x^{2} - 118 x + 41 = 0

What are the solutions to the equation (x+1)^3-(x-1)^3=7 ?
The solutions to the equation (x+1)^3-(x-1)^3=7 are x=sqrt(5/6),x=-sqrt(5/6)
Find the zeros of (x+1)^3-(x-1)^3=7
The zeros of (x+1)^3-(x-1)^3=7 are x=sqrt(5/6),x=-sqrt(5/6)