What are the solutions to the equation 36x^2-36x+2=0 ?

The solutions to the equation 36x^2-36x+2=0 are x=(3+sqrt(7))/6 ,x=(3-sqrt(7))/6

Find the zeros of 36x^2-36x+2=0

The zeros of 36x^2-36x+2=0 are x=(3+sqrt(7))/6 ,x=(3-sqrt(7))/6

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36 x^{2} - 36 x + 2 = 0

x = \frac{3 + 7}{6}, x = \frac{3 - 7}{6}

Decimal Notation

x = 0.94095 \dots, x = 0.05904 \dots

Solution steps

36 x^{2} - 36 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 36 \cdot 2}{2 \cdot 36}

(- 36)^{2} - 4 \cdot 36 \cdot 2 = 127

x_{1, 2} = \frac{- ( - 36 ) \pm 12 7}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 12 7}{2 \cdot 36}, x_{2} = \frac{- ( - 36 ) - 12 7}{2 \cdot 36}

x = \frac{- ( - 36 ) + 12 7}{2 \cdot 36} : \frac{3 + 7}{6}

x = \frac{- ( - 36 ) - 12 7}{2 \cdot 36} : \frac{3 - 7}{6}

The solutions to the quadratic equation are:

x = \frac{3 + 7}{6}, x = \frac{3 - 7}{6}

9^{2} + 1 5^{2} = x^{2}

(x + 4)^{2} + (x - 3)^{2} = (x - 1)^{2} + 36

- 5 (6 x + 7) (3 x + 2) = 0

x, x^{2} + y^{2} - 2 x - 2 y + 11 = 0

3 - 3 x^{(2)} = 0

What are the solutions to the equation 36x^2-36x+2=0 ?
The solutions to the equation 36x^2-36x+2=0 are x=(3+sqrt(7))/6 ,x=(3-sqrt(7))/6
Find the zeros of 36x^2-36x+2=0
The zeros of 36x^2-36x+2=0 are x=(3+sqrt(7))/6 ,x=(3-sqrt(7))/6