What are the solutions to the equation -5(6x+7)(3x+2)=0 ?

The solutions to the equation -5(6x+7)(3x+2)=0 are x=-7/6 ,x=-2/3

Find the zeros of -5(6x+7)(3x+2)=0

The zeros of -5(6x+7)(3x+2)=0 are x=-7/6 ,x=-2/3

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- 5 (6 x + 7) (3 x + 2) = 0

x = - \frac{7}{6}, x = - \frac{2}{3}

Decimal Notation

x = - 1.16666 \dots, x = - 0.66666 \dots

Solution steps

- 5 (6 x + 7) (3 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

6 x + 7 = 0 or 3 x + 2 = 0

Solve

6 x + 7 = 0 : x = - \frac{7}{6}

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{7}{6}, x = - \frac{2}{3}

x, x^{2} + y^{2} - 2 x - 2 y + 11 = 0

3 - 3 x^{(2)} = 0

x^{2} - 9 x - 162 = 0

4 - x^{2} = 4 - 3 x

0 = - 3 (x + 2)^{2} + 4

What are the solutions to the equation -5(6x+7)(3x+2)=0 ?
The solutions to the equation -5(6x+7)(3x+2)=0 are x=-7/6 ,x=-2/3
Find the zeros of -5(6x+7)(3x+2)=0
The zeros of -5(6x+7)(3x+2)=0 are x=-7/6 ,x=-2/3