What are the solutions to the equation 0=-3(x+2)^2+4 ?

The solutions to the equation 0=-3(x+2)^2+4 are x= 2/(sqrt(3))-2,x=-2/(sqrt(3))-2

Find the zeros of 0=-3(x+2)^2+4

The zeros of 0=-3(x+2)^2+4 are x= 2/(sqrt(3))-2,x=-2/(sqrt(3))-2

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0 = - 3 (x + 2)^{2} + 4

x = \frac{2}{3} - 2, x = - \frac{2}{3} - 2

Decimal Notation

x = - 0.84529 \dots, x = - 3.15470 \dots

Solution steps

0 = - 3 (x + 2)^{2} + 4

Switch sides

- 3 (x + 2)^{2} + 4 = 0

Move

4

to the right side

- 3 (x + 2)^{2} = - 4

Divide both sides by

- 3

(x + 2)^{2} = \frac{4}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = \frac{4}{3} : x = \frac{2}{3} - 2

Solve

x + 2 = - \frac{4}{3} : x = - \frac{2}{3} - 2

The solutions to the quadratic equation are:

x = \frac{2}{3} - 2, x = - \frac{2}{3} - 2

300 x^{2} - 60 x - 144 = 0

2 x^{2} - 18 x + 1 = 0

v^{2} - 5 v - 14 = 0

- x^{2} + 8 x = 7

120 x^{2} + x - 75 = 0

What are the solutions to the equation 0=-3(x+2)^2+4 ?
The solutions to the equation 0=-3(x+2)^2+4 are x= 2/(sqrt(3))-2,x=-2/(sqrt(3))-2
Find the zeros of 0=-3(x+2)^2+4
The zeros of 0=-3(x+2)^2+4 are x= 2/(sqrt(3))-2,x=-2/(sqrt(3))-2