What are the solutions to the equation v^2-5v-14=0 ?

The solutions to the equation v^2-5v-14=0 are v=7,v=-2

Find the zeros of v^2-5v-14=0

The zeros of v^2-5v-14=0 are v=7,v=-2

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v^{2} - 5 v - 14 = 0

v = 7, v = - 2

Solution steps

v^{2} - 5 v - 14 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

v_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, v_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

v = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

v = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

v = 7, v = - 2

- x^{2} + 8 x = 7

120 x^{2} + x - 75 = 0

\frac{1}{3} x^{2} - 5 x + 25 = 0

(6 + y)^{2} + y^{2} = 218

2 x^{2} - 4 x - 8 = - x^{2} + x

What are the solutions to the equation v^2-5v-14=0 ?
The solutions to the equation v^2-5v-14=0 are v=7,v=-2
Find the zeros of v^2-5v-14=0
The zeros of v^2-5v-14=0 are v=7,v=-2