What are the solutions to the equation -x^2+7=-42 ?

The solutions to the equation -x^2+7=-42 are x=7,x=-7

Find the zeros of -x^2+7=-42

The zeros of -x^2+7=-42 are x=7,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 7 = - 42

x = 7, x = - 7

Solution steps

- x^{2} + 7 = - 42

Move

7

to the right side

- x^{2} = - 49

Divide both sides by

- 1

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

t^{2} - 5 t - 14 = 0

3 x^{2} - 6 + 4 x^{2} = 15

x^{2} - 7 x + 10

x, x^{2} + y^{2} + z^{2} - 2 x + 6 y + 8 z + 1 = 0

t^{2} = 50

What are the solutions to the equation -x^2+7=-42 ?
The solutions to the equation -x^2+7=-42 are x=7,x=-7
Find the zeros of -x^2+7=-42
The zeros of -x^2+7=-42 are x=7,x=-7