What are the solutions to the equation y^2-y-56=0 ?

The solutions to the equation y^2-y-56=0 are y=8,y=-7

Find the zeros of y^2-y-56=0

The zeros of y^2-y-56=0 are y=8,y=-7

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y^{2} - y - 56 = 0

y = 8, y = - 7

Solution steps

y^{2} - y - 56 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 56) = 15

y_{1, 2} = \frac{- ( - 1 ) \pm 15}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 15}{2 \cdot 1}, y_{2} = \frac{- ( - 1 ) - 15}{2 \cdot 1}

y = \frac{- ( - 1 ) + 15}{2 \cdot 1} : 8

y = \frac{- ( - 1 ) - 15}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

y = 8, y = - 7

3 a^{2} - 17 = 31

2 x^{2} - 14 x + 49 = 0

x^{2} + 14 x + 36 = 0

k^{2} = 9

x^{2} - 25 = 0

What are the solutions to the equation y^2-y-56=0 ?
The solutions to the equation y^2-y-56=0 are y=8,y=-7
Find the zeros of y^2-y-56=0
The zeros of y^2-y-56=0 are y=8,y=-7