What are the solutions to the equation x^2+8x-32=0 ?

The solutions to the equation x^2+8x-32=0 are x=4(sqrt(3)-1),x=-4(1+sqrt(3))

Find the zeros of x^2+8x-32=0

The zeros of x^2+8x-32=0 are x=4(sqrt(3)-1),x=-4(1+sqrt(3))

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x^{2} + 8 x - 32 = 0

x = 4 (3 - 1), x = - 4 (1 + 3)

Decimal Notation

x = 2.92820 \dots, x = - 10.92820 \dots

Solution steps

x^{2} + 8 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 32) = 83

x_{1, 2} = \frac{- 8 \pm 8 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8 3}{2 \cdot 1}, x_{2} = \frac{- 8 - 8 3}{2 \cdot 1}

x = \frac{- 8 + 8 3}{2 \cdot 1} : 4 (3 - 1)

x = \frac{- 8 - 8 3}{2 \cdot 1} : - 4 (1 + 3)

The solutions to the quadratic equation are:

x = 4 (3 - 1), x = - 4 (1 + 3)

z, x^{3} z^{2} - 5 x y^{5} z = x^{2} + y^{3}

5 x^{2} - x + 6 = 5 - 7 x - 4 x^{2}

y, (x - 2)^{2} + (y + 3)^{2} = 4

y, (x - 2)^{2} + (y + 3)^{2} = 9

7 x^{2} = 1

What are the solutions to the equation x^2+8x-32=0 ?
The solutions to the equation x^2+8x-32=0 are x=4(sqrt(3)-1),x=-4(1+sqrt(3))
Find the zeros of x^2+8x-32=0
The zeros of x^2+8x-32=0 are x=4(sqrt(3)-1),x=-4(1+sqrt(3))