What are the solutions to the equation 5x^2-x+6=5-7x-4x^2 ?

The solutions to the equation 5x^2-x+6=5-7x-4x^2 are x=-1/3

Find the zeros of 5x^2-x+6=5-7x-4x^2

The zeros of 5x^2-x+6=5-7x-4x^2 are x=-1/3

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5 x^{2} - x + 6 = 5 - 7 x - 4 x^{2}

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

5 x^{2} - x + 6 = 5 - 7 x - 4 x^{2}

Move

4 x^{2}

to the left side

9 x^{2} - x + 6 = 5 - 7 x

Move

7 x

to the left side

9 x^{2} + 6 x + 6 = 5

Move

5

to the left side

9 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

x = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

x = - \frac{1}{3}

The solution to the quadratic equation is:

x = - \frac{1}{3}

y, (x - 2)^{2} + (y + 3)^{2} = 4

y, (x - 2)^{2} + (y + 3)^{2} = 9

7 x^{2} = 1

- 2 (x - 4)^{2} = 11

x^{2} - 11 x + 12 = 0

What are the solutions to the equation 5x^2-x+6=5-7x-4x^2 ?
The solutions to the equation 5x^2-x+6=5-7x-4x^2 are x=-1/3
Find the zeros of 5x^2-x+6=5-7x-4x^2
The zeros of 5x^2-x+6=5-7x-4x^2 are x=-1/3