What are the solutions to the equation -2(x-4)^2=11 ?

The solutions to the equation -2(x-4)^2=11 are x=isqrt(11/2)+4,x=-isqrt(11/2)+4

Find the zeros of -2(x-4)^2=11

The zeros of -2(x-4)^2=11 are x=isqrt(11/2)+4,x=-isqrt(11/2)+4

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- 2 (x - 4)^{2} = 11

x = i \frac{11}{2} + 4, x = - i \frac{11}{2} + 4

Solution steps

- 2 (x - 4)^{2} = 11

Divide both sides by

- 2

(x - 4)^{2} = - \frac{11}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - \frac{11}{2} : x = i \frac{11}{2} + 4

Solve

x - 4 = - - \frac{11}{2} : x = - i \frac{11}{2} + 4

The solutions to the quadratic equation are:

x = i \frac{11}{2} + 4, x = - i \frac{11}{2} + 4

x^{2} - 11 x + 12 = 0

9 x^{2} + 12 x + 4 = 5

3 x^{2} = - 5 x + 3

s^{2} - s + 2

2 x^{2} - 4 x + 1 = 0

What are the solutions to the equation -2(x-4)^2=11 ?
The solutions to the equation -2(x-4)^2=11 are x=isqrt(11/2)+4,x=-isqrt(11/2)+4
Find the zeros of -2(x-4)^2=11
The zeros of -2(x-4)^2=11 are x=isqrt(11/2)+4,x=-isqrt(11/2)+4