What are the solutions to the equation 9x^2+12x+4=5 ?

The solutions to the equation 9x^2+12x+4=5 are x=(-2+sqrt(5))/3 ,x=-(2+sqrt(5))/3

Find the zeros of 9x^2+12x+4=5

The zeros of 9x^2+12x+4=5 are x=(-2+sqrt(5))/3 ,x=-(2+sqrt(5))/3

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9 x^{2} + 12 x + 4 = 5

x = \frac{- 2 + 5}{3}, x = - \frac{2 + 5}{3}

Decimal Notation

x = 0.07868 \dots, x = - 1.41202 \dots

Solution steps

9 x^{2} + 12 x + 4 = 5

Move

5

to the left side

9 x^{2} + 12 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 (- 1) = 65

x_{1, 2} = \frac{- 12 \pm 6 5}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 12 + 6 5}{2 \cdot 9}, x_{2} = \frac{- 12 - 6 5}{2 \cdot 9}

x = \frac{- 12 + 6 5}{2 \cdot 9} : \frac{- 2 + 5}{3}

x = \frac{- 12 - 6 5}{2 \cdot 9} : - \frac{2 + 5}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 5}{3}, x = - \frac{2 + 5}{3}

3 x^{2} = - 5 x + 3

s^{2} - s + 2

2 x^{2} - 4 x + 1 = 0

2 x^{2} - 48 = 0

4 x^{2} + 10 = 46

What are the solutions to the equation 9x^2+12x+4=5 ?
The solutions to the equation 9x^2+12x+4=5 are x=(-2+sqrt(5))/3 ,x=-(2+sqrt(5))/3
Find the zeros of 9x^2+12x+4=5
The zeros of 9x^2+12x+4=5 are x=(-2+sqrt(5))/3 ,x=-(2+sqrt(5))/3