What are the solutions to the equation 2x^2-48=0 ?

The solutions to the equation 2x^2-48=0 are x=2sqrt(6),x=-2sqrt(6)

Find the zeros of 2x^2-48=0

The zeros of 2x^2-48=0 are x=2sqrt(6),x=-2sqrt(6)

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2 x^{2} - 48 = 0

x = 26, x = - 26

Decimal Notation

x = 4.89897 \dots, x = - 4.89897 \dots

Solution steps

2 x^{2} - 48 = 0

Move

48

to the right side

2 x^{2} = 48

Divide both sides by

2

x^{2} = 24

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 24, x = - 24

24 = 26

- 24 = - 26

x = 26, x = - 26

4 x^{2} + 10 = 46

b, x^{2} - 12 x + a = (x + b)^{2}

(2 x^{2} - 1) = 0

49 v^{2} + 16 = - 56 v

0.012 x^{2} - 0.583 x + 35.727 = 40

What are the solutions to the equation 2x^2-48=0 ?
The solutions to the equation 2x^2-48=0 are x=2sqrt(6),x=-2sqrt(6)
Find the zeros of 2x^2-48=0
The zeros of 2x^2-48=0 are x=2sqrt(6),x=-2sqrt(6)