What are the solutions to the equation 2x^2+15=-17 ?

The solutions to the equation 2x^2+15=-17 are x=4i,x=-4i

Find the zeros of 2x^2+15=-17

The zeros of 2x^2+15=-17 are x=4i,x=-4i

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2 x^{2} + 15 = - 17

x = 4 i, x = - 4 i

Solution steps

2 x^{2} + 15 = - 17

Move

15

to the right side

2 x^{2} = - 32

Divide both sides by

2

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

8 x^{2} - 392 = 0

g, g (n - 7) g = \frac{x ^{2} - 6}{7 x}

- 6 x^{2} + 18 x = 0

m^{2} + 6 m + 25 = 0

0 = - x^{2} - x + 2

What are the solutions to the equation 2x^2+15=-17 ?
The solutions to the equation 2x^2+15=-17 are x=4i,x=-4i
Find the zeros of 2x^2+15=-17
The zeros of 2x^2+15=-17 are x=4i,x=-4i