What are the solutions to the equation (x^2)/8-x=0 ?

The solutions to the equation (x^2)/8-x=0 are x=8,x=0

Find the zeros of (x^2)/8-x=0

The zeros of (x^2)/8-x=0 are x=8,x=0

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\frac{x ^{2}}{8} - x = 0

x = 8, x = 0

Solution steps

\frac{x ^{2}}{8} - x = 0

Multiply both sides by

8

x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

x = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 8, x = 0

- 5 x^{2} + 8 x - 9 = 0

7 x^{2} + 3 x + 2 = 0

x, \frac{x ^{2}}{4} + \frac{y ^{2}}{9} + \frac{z ^{2}}{9} = 1

x^{2} + (x + 2)^{2} = 452

4 x^{2} - 28 x + 45 = 0

What are the solutions to the equation (x^2)/8-x=0 ?
The solutions to the equation (x^2)/8-x=0 are x=8,x=0
Find the zeros of (x^2)/8-x=0
The zeros of (x^2)/8-x=0 are x=8,x=0