What are the solutions to the equation ax^2-abx=0 ?

The solutions to the equation ax^2-abx=0 are x=b,x=0;\quad a\ne 0

Find the zeros of ax^2-abx=0

The zeros of ax^2-abx=0 are x=b,x=0;\quad a\ne 0

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a x^{2} - ab x = 0

x = b, x = 0; a \neq = 0

Solution steps

a x^{2} - ab x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - ab ) \pm ( - ab ) ^{2} - 4 a \cdot 0}{2 a}

Simplify

(- ab)^{2} - 4 a \cdot 0 : ab

x_{1, 2} = \frac{- ( - ab ) \pm ab}{2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- ( - ab ) + ab}{2 a}, x_{2} = \frac{- ( - ab ) - ab}{2 a}

x = \frac{- ( - ab ) + ab}{2 a} : b

x = \frac{- ( - ab ) - ab}{2 a} : 0

The solutions to the quadratic equation are:

x = b, x = 0; a \neq = 0

x^{2} + (x + 28)^{2} = 6 8^{2}

0.022 - 0.22 x - x^{2} = 0

6 n^{2} - 19 n + 10 = 0

x^{2} = \frac{1}{2} (30 - x)^{2}

5 n^{2} - 20 n + 6 = 0

What are the solutions to the equation ax^2-abx=0 ?
The solutions to the equation ax^2-abx=0 are x=b,x=0;\quad a\ne 0
Find the zeros of ax^2-abx=0
The zeros of ax^2-abx=0 are x=b,x=0;\quad a\ne 0