What are the solutions to the equation 3x^2+14x+16=0 ?

The solutions to the equation 3x^2+14x+16=0 are x=-2,x=-8/3

Find the zeros of 3x^2+14x+16=0

The zeros of 3x^2+14x+16=0 are x=-2,x=-8/3

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3 x^{2} + 14 x + 16 = 0

x = - 2, x = - \frac{8}{3}

Decimal Notation

x = - 2, x = - 2.66666 \dots

Solution steps

3 x^{2} + 14 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 \cdot 16}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 \cdot 16 = 2

x_{1, 2} = \frac{- 14 \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 14 + 2}{2 \cdot 3}, x_{2} = \frac{- 14 - 2}{2 \cdot 3}

x = \frac{- 14 + 2}{2 \cdot 3} : - 2

x = \frac{- 14 - 2}{2 \cdot 3} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = - 2, x = - \frac{8}{3}

4 y = 7 y^{2} - 3

3^{2} + 1^{2} = x^{2}

3 x^{2} - 24 x

(x + 2)^{2} = 50

3 x^{2} - 12 x

What are the solutions to the equation 3x^2+14x+16=0 ?
The solutions to the equation 3x^2+14x+16=0 are x=-2,x=-8/3
Find the zeros of 3x^2+14x+16=0
The zeros of 3x^2+14x+16=0 are x=-2,x=-8/3