What are the solutions to the equation 4(x^2-1)=21 ?

The solutions to the equation 4(x^2-1)=21 are x= 5/2 ,x=-5/2

Find the zeros of 4(x^2-1)=21

The zeros of 4(x^2-1)=21 are x= 5/2 ,x=-5/2

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4 (x^{2} - 1) = 21

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 2.5, x = - 2.5

Solution steps

4 (x^{2} - 1) = 21

Divide both sides by

4

x^{2} - 1 = \frac{21}{4}

Move

1

to the right side

x^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{4}, x = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

15 (2 a - 2) = 5 (a^{2} - 1)

2 n^{2} - 14 n + 3 = 3

s^{2} + 3 s + 4

x, x^{2} - 3 m x + 2 m^{2} = 0

- 3 x^{2} = 2 x + 5

What are the solutions to the equation 4(x^2-1)=21 ?
The solutions to the equation 4(x^2-1)=21 are x= 5/2 ,x=-5/2
Find the zeros of 4(x^2-1)=21
The zeros of 4(x^2-1)=21 are x= 5/2 ,x=-5/2