What are the solutions to the equation m^2-8m+41=0 ?

The solutions to the equation m^2-8m+41=0 are m=4+5i,m=4-5i

Find the zeros of m^2-8m+41=0

The zeros of m^2-8m+41=0 are m=4+5i,m=4-5i

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m^{2} - 8 m + 41 = 0

m = 4 + 5 i, m = 4 - 5 i

Solution steps

m^{2} - 8 m + 41 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 41}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 41 : 10 i

m_{1, 2} = \frac{- ( - 8 ) \pm 10 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 8 ) + 10 i}{2 \cdot 1}, m_{2} = \frac{- ( - 8 ) - 10 i}{2 \cdot 1}

m = \frac{- ( - 8 ) + 10 i}{2 \cdot 1} : 4 + 5 i

m = \frac{- ( - 8 ) - 10 i}{2 \cdot 1} : 4 - 5 i

The solutions to the quadratic equation are:

m = 4 + 5 i, m = 4 - 5 i

- 6 x^{2} + 32 = 0

r^{2} + 3 r = 6

\frac{3 x ^{2}}{2} + 4 x - \frac{2}{3} = 0

18 x^{2} - 16 x - 8 = - 16 x

x^{2} + 3 x - 26 = 0

What are the solutions to the equation m^2-8m+41=0 ?
The solutions to the equation m^2-8m+41=0 are m=4+5i,m=4-5i
Find the zeros of m^2-8m+41=0
The zeros of m^2-8m+41=0 are m=4+5i,m=4-5i